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Verify each of the following:
(i)`sin 60^0 cos 30^0-cos 60^0 sin 30^0`
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Solution
`sin 60^0 cos 30^0-cos 60^0 sin 30^0`
=`(sqrt(3)/2)xx(sqrt(3)/2) -(1/2)xx(1/2) = 3/4-1/4=2/4=1/2`
Also, `sin 30^0 =1/2`
∴ `sin 60^0 cos 30^0-cos 60^0 sin 30^0= sin 30^0`
Concept: Trigonometric Ratios and Its Reciprocal
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