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Solution - Find the vector equation of a plane which is at a distance of 5 units from the origin and its normal vector is 2i-3j+6k - Vector and Cartesian Equation of a Plane

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Question

Find the vector equation of a plane which is at a distance of 5 units from the origin and its normal vector is `2hati-3hatj+6hatk`

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Reference Material

Solution for question: Find the vector equation of a plane which is at a distance of 5 units from the origin and its normal vector is 2i-3j+6k concept: Vector and Cartesian Equation of a Plane. For the courses CBSE (Arts), CBSE (Commerce), CBSE (Science)
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