HSC Science (Electronics) 12th Board ExamMaharashtra State Board
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Solution for Find the cartesian form of the equation of the plane - HSC Science (Electronics) 12th Board Exam - Mathematics and Statistics

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Question

Find the cartesian form of the equation of the plane `bar r=(hati+hatj)+s(hati-hatj+2hatk)+t(hati+2hatj+hatj)`

Solution

The equation `barr=bara+sbarb+tbarc` represents a plane passing through a point having position vector a and parallel to the vectors b and c .

Here, `bara=hati+hatj, barb=hati-hatj+2hatk and barc=hati+2hatj+hatk`

The given plane is perpendicular to the vector `barn`

Vector equation of the plane in scalar product form is `barr.barn=bara.barn`

`therefore x(-5)+y(1)+z(3)=-4`

`therefore -5x+y+3z=-4`

`therefore 5x-y-3z=4`

which is the cartesian form of the equation of the plane

  Is there an error in this question or solution?

APPEARS IN

 2015-2016 (July) (with solutions)
Question 2.1.3 | 3 marks
Solution for question: Find the cartesian form of the equation of the plane concept: Vector and Cartesian Equation of a Plane. For the courses HSC Science (Electronics), HSC Science (Computer Science), HSC Arts, HSC Science (General)
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