HSC Science (Electronics) 12th Board ExamMaharashtra State Board
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Solution for Find the cartesian form of the equation of the plane - HSC Science (Electronics) 12th Board Exam - Mathematics and Statistics

ConceptVector and Cartesian Equation of a Plane

Question

Find the cartesian form of the equation of the plane bar r=(hati+hatj)+s(hati-hatj+2hatk)+t(hati+2hatj+hatj)

Solution

The equation barr=bara+sbarb+tbarc represents a plane passing through a point having position vector a and parallel to the vectors b and c .

Here, bara=hati+hatj, barb=hati-hatj+2hatk and barc=hati+2hatj+hatk

The given plane is perpendicular to the vector barn

Vector equation of the plane in scalar product form is barr.barn=bara.barn

therefore x(-5)+y(1)+z(3)=-4

therefore -5x+y+3z=-4

therefore 5x-y-3z=4

which is the cartesian form of the equation of the plane

Is there an error in this question or solution?

APPEARS IN

2015-2016 (July) (with solutions)
Question 2.1.3 | 3 marks
Solution for question: Find the cartesian form of the equation of the plane concept: Vector and Cartesian Equation of a Plane. For the courses HSC Science (Electronics), HSC Science (Computer Science), HSC Arts, HSC Science (General)
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