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Find the Cartesian Equation of the Following Planes: Vecr.[(S-2t)Hati + (3 - T)Hatj + (2s + T)Hatk] = 15 - CBSE (Science) Class 12 - Mathematics

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Question

Find the Cartesian equation of the following planes:

`vecr.[(s-2t)hati + (3 - t)hatj + (2s + t)hatk] = 15`

Solution

`vecr.[(s-2t)hati + (3 - t)hatj + (2s + t)hatk] = 15`  ....(1)

For any arbitrary point P (xyz) on the plane, position vector `vecr` is given by,

`vecr = xhati + yhatj - zhatk`

Substituting the value of `hatr` in equation (1), we obtain

This is the Cartesian equation of the given plane.

  Is there an error in this question or solution?

APPEARS IN

 NCERT Solution for Mathematics Textbook for Class 12 (2018 to Current)
Chapter 11: Three Dimensional Geometry
Q: 3.3 | Page no. 493
Solution Find the Cartesian Equation of the Following Planes: Vecr.[(S-2t)Hati + (3 - T)Hatj + (2s + T)Hatk] = 15 Concept: Vector and Cartesian Equation of a Plane.
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