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Find the Equation of the Line Passing Through (–3, 5) and Perpendicular to the Line Through the Points (2, 5) and (–3, 6). - CBSE (Arts) Class 11 - Mathematics

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Question

Find the equation of the line passing through (–3, 5) and perpendicular to the line through the points (2, 5) and (–3, 6).

Solution

The slope of the line joining the points (2, 5) and (–3, 6) is m = `(6-5)/(-3-2) = 1/(-5)`

We know that two non-vertical lines are perpendicular to each other if and only if their slopes are negative reciprocals of each other.

Therefore, slope of the line perpendicular to the line through the points (2, 5) and (–3, 6)

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Solution Find the Equation of the Line Passing Through (–3, 5) and Perpendicular to the Line Through the Points (2, 5) and (–3, 6). Concept: Various Forms of the Equation of a Line.
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