Using truth table prove that :
`~p^^q-=(p vv q)^^~p`
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Solution
| 1 | 2 | 3 | 4 | 5 | 6 |
| p | q | ~p |
`~p^^q` |
`pvvq` |
`(pvvq)^^~p` |
| T | T | F | F | T | F |
| T | F | F | F | T | F |
| F | T | T | T | T | T |
| F | F | T | F | F | F |
Column (4) and (6) are identical truth value
`therefore ~p^^q-=(p vv q)^^~p`
Concept: Mathematical Logic - Truth Tables of Compound Statements
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