Using truth table examine whether the following statement pattern is tautology, contradiction or contingency `(p^^~q) harr (p->q)`

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#### Solution

`p` |
`q` |
`~q` |
`p^^~q` |
`p->q` |
`(p^^~q)harr(p->q)` |

T | T | F | F | T | F |

T | F | T | T | F | F |

F | T | F | F | T | F |

F | F | T | F | T | F |

All the entries in the last column of the above truth table are F.

`(p^^~q) harr (p->q)` is is a contradiction

Is there an error in this question or solution?

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