Using the determinants given below form two linear equations and solve them
D = `|(5, 7),(2, -3)|`, Dy = `|(5, 4),(2,-10)|`
Solution
If a1x + b1y = c1 and a2x + b2y = c2 are linear equations in two variables, then
D = `|("a"_1, "b"_1),("a"_2, "a"_2)|`
Dx = `|("c"_1, "b"_1),("c"_2, "b"_2)|`
Dy = `|("a"_1, "c"_1),("a"_2, "c"_2)|` ......(i)
Given, D = `|(5, 7),(2, -3)|`
Dy = `|(5, 4),(2, -10)|`
Comparing these determinants with equation (i), we get
a1 = 5, b1 = 7, c1 = 4
a2 = 2, b2 = –3, c2 = –10
∴ The equations are
5x + 7y = 4 ......(ii)
2x– 3y = –10 ......(iii)
Multiplying equation (ii) by 3 and equation (iii) by 7, we get
15x + 21y = 12 ......(iv)
14x – 21y = –70 ......(v)
Adding equations (iv) and (v), we get
15x + 21y = 12
+ 14x – 21y = – 70
29x = – 58
∴ x = `-58/29` = – 2
Substituting x = –2 in equation (ii), we get
5(–2) + 7y = 4
∴ –10 + 7y = 4
∴ 7y = 14
∴ y = `14/7` = 2
∴ x = –2 and y = 2 is the solution of the equations 5x + 7y = 4 and 2x – 3y = –10.