Sum

Using the mesh analysis find the mesh current in the direction shown and also find the voltage across A and B terminals.

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#### Solution

Applying KVL to mesh a

−3πΌ_{π} − 2πΌ_{π} − 4(πΌ_{π} − πΌ_{π} ) + 10 = 0

−3πΌ_{π} − 2πΌ_{π} − 4πΌ_{π} + 4πΌ_{π} + 10

Applying KVL to mesh b

-10 + 6πΌ_{π} + 8πΌ_{π} − 4(πΌ_{π} − πΌ_{π}) = 0

6πΌ_{π} + 8πΌ_{π} − 4πΌ_{π} + 4πΌ_{π} = 10

-4πΌ_{π} + 18πΌ_{π} = 10 ………..(2)

From (1) and (2) we get,

πΌ_{π} = 1.5068A and πΌ_{π} = 0.890A

For voltage:-

Apply KVL to mesh

-V+3πΌ_{π} + 8πΌ_{π} = 0

V = 3πΌ_{π} + 8πΌ_{π}

V = 3× 1.5068 + 0.89 × 8

V = 11.640V

Concept: Mesh Analysis

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