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Using Integration Finds the Area of the Region Bounded by the Triangle Whose Vertices Are (–1, 0), (1, 3) and (3, 2). - Mathematics

Using integration finds the area of the region bounded by the triangle whose vertices are (–1, 0), (1, 3) and (3, 2).

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Solution

BL and CM are drawn perpendicular to x-axis.

It can be observed in the following figure that,

Area (ΔACB) = Area (ALBA) + Area (BLMCB) – Area (AMCA) … (1)

Therefore, from equation (1), we obtain

Area (ΔABC) = (3 + 5 – 4) = 4 units

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APPEARS IN

NCERT Class 12 Maths
Chapter 8 Application of Integrals
Q 4 | Page 371
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