Sum

**Use the table given below to find:**(a) The actual class limits of the fourth class.

(b) The class boundaries of the sixth class.

(c) The class mark of the third class.

(d) The upper and lower limits of the fifth class.

(e) The size of the third class.

Class Interval |
Frequency |

30 - 34 | 7 |

35 - 39 | 10 |

40 - 44 | 12 |

45 - 49 | 13 |

50 - 54 | 8 |

55 - 59 | 4 |

Advertisement Remove all ads

#### Solution

(a) The actual class limit of the fourth class will be **44.5 - 49.5.**

(b) The class boundaries of the sixth class will be **54.5 - 59.5**

(c) The class mark of the third class will be the average of the lower bound and the upper bound of the interval. Therefore the class mark will be: `( 40 + 44)/( 2)` = 42

(d) The upper and lower limit of the fifth class is **54 and 50** respectively.

(e) The size of the third class will be **44 - 40 + 1 = 5.**

Concept: Tabulation of Data

Is there an error in this question or solution?

Advertisement Remove all ads

#### APPEARS IN

Advertisement Remove all ads

Advertisement Remove all ads