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Sum

Use the following figure to find the value of x

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#### Solution

The sum of exterior angles of a quadrilateral

⇒ y + 80° + 60° + 90° = 360°

⇒ y + 230° = 360°

⇒ y = 360° – 230° = 130°

At vertex A,

∠y + ∠x = 180° (Linear pair)

x = 180° – 130°

⇒ x = 50°

Is there an error in this question or solution?