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# Use binomial theorem to evaluate the following upto four places of decimal (0.98)–3 - Mathematics and Statistics

Sum

Use binomial theorem to evaluate the following upto four places of decimal

(0.98)–3

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#### Solution

(0.98)–3

= (1 – 0.02)–3

= 1 - (-3) (0.02) + ((-3)(-3 - 1))/(2!) (0.02)^2 - ((-3)(-3 - 1)(-3 - 2))/(3!) (0.02)^3 + ......

= 1 + 0.06 + (-3(-4))/2 (0.02)^2 - ((-3)(-4)(-5))/6 (0.02)^3 + ......

= 1 + 0.06 + 0.0024 + 0.00008 + ….

= 1.06248

= 1.0625

Concept: Binomial Theorem for Negative Index Or Fraction
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#### APPEARS IN

Balbharati Mathematics and Statistics 2 (Arts and Science) 11th Standard Maharashtra State Board
Chapter 4 Methods of Induction and Binomial Theorem
Exercise 4.4 | Q 4. (v) | Page 82
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