HSC Science (General) 12th Board ExamMaharashtra State Board
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Obtain an Expression for Linear Acceleration of the Particle Performing Non-uniform Circular Motion. - HSC Science (General) 12th Board Exam - Physics

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Question

For a particle performing uniform circular motion `vecv=vecomegaxxvecr`obtain an expression for linear acceleration of the particle performing non-uniform circular motion.

Solution

`vecv=vecomegaxxvecr`

`vec(dv)/dt=vec(domega)/dtxxvecr+vecomegaxxvec(dr)/dt`

where 

`(dvecomega)/dt=vecalpha,`

`(dr)/dt=vecv`

`(dvecv)/dt=veca`

`:.veca=vecalphaxxvecr+vecomegaxxvecv`

  Is there an error in this question or solution?

APPEARS IN

 2013-2014 (March) (with solutions)
Question 1.6 | 2.00 marks

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Solution Obtain an Expression for Linear Acceleration of the Particle Performing Non-uniform Circular Motion. Concept: Uniform Circular Motion.
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