#### Question

A vehicle is moving on a circular track whose surface is inclined towards the horizon at an angle of 10°. The maximum velocity with which it can move safely is 36 km / hr. Calculate the length of the circular track. [π = 3.142]

#### Solution

Given `v=36kmh^-1=36xx5/18=10m/s, theta=10^@`

To Find: Length of circular track s(l)

formulae: `r=(v_max^2)/(g tan theta)`

`r=(10^2)/(9.8xxtan 10^@)`

`=57.88 m`

`l=2piR=2xx3.14xx57.88=363.48m`

The length of the circular track is 363.48 m.

Is there an error in this question or solution?

#### APPEARS IN

Solution A Vehicle is Moving on a Circular Track Whose Surface is Inclined Towards the Horizon at an Angle of 10°. the Maximum Velocity with Which It Can Move Safely is 36 Km / Hr. Calculate the Length of the Circular Track Concept: Uniform Circular Motion.