# Solution - A particle rotates in U.C.M. with tangential velocity V along a horizontal circle of diameter ‘D' . Total angular displacement of the particle in time 't' is - Uniform Circular Motion

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#### Question

A particle rotates in U.C.M. with tangential velocity V along a horizontal circle of diameter ‘D' . Total angular displacement of the particle in time 't' is..........

(a) vt

(b) (v/D)-t

(c) vt/2D

(d) 2vt/D

#### Solution

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Solution for question: A particle rotates in U.C.M. with tangential velocity V along a horizontal circle of diameter ‘D' . Total angular displacement of the particle in time 't' is concept: Uniform Circular Motion. For the courses 12th HSC Science (Computer Science), 12th HSC Science (Electronics), 12th HSC Science (General)
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