Question
A particle rotates in U.C.M. with tangential velocity V along a horizontal circle of diameter ‘D' . Total angular displacement of the particle in time 't' is..........
(a) vt
(b) (v/D)-t
(c) vt/2D
(d) 2vt/D
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Solution
`2(vt)/D`
Velocity= v ; Diameter= D →Radius= `D/2`
`omega=theta/t andv=r*omega`
`therefore v=D/2*theta/t`
`therefore theta=(2vt)/D`
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Solution for question: A particle rotates in U.C.M. with tangential velocity V along a horizontal circle of diameter ‘D' . Total angular displacement of the particle in time 't' is concept: Uniform Circular Motion. For the courses HSC Science (Electronics), HSC Science (Computer Science), HSC Science (General)