#### Question

Use product `[(1,-1,2),(0,2,-3),(3,-2,4)][(-2,0,1),(9,2,-3),(6,1,-2)]` to solve the system of equations x + 3z = 9, −x + 2y − 2z = 4, 2x − 3y + 4z = −3

#### Solution

Since, A × B = I,

∴ B = A^{−1} .....(1)

Now, the given system of equations is

x + 3z = 9

−x + 2y − 2z = 4

2x − 3y + 4z = −3

This can also be represented as,

Hence, *x* = 0, *y* = 5 and *z* = 3.

Is there an error in this question or solution?

Solution Use Product `Matrix[(1,-1,2),(0,2,-3),(3,-2,4)][(-2,0,1),(9,2,-3),(6,1,-2)]` To Solve the System of Equations X + 3z = 9, −X + 2y − 2z = 4, 2x − 3y + 4z = −3 Concept: Types of Matrices.