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In a Single Throw of Two Dice, Find the Probability Of: a Total of at Most 10 - ICSE Class 10 - Mathematics

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Question

In a single throw of two dice, find the probability of: 

a total of at most 10

Solution

The  number of possible outcomes is `6xx6=36`,  We write them as given below:  

1,11,21,,31,41,51,6 

2,12,22,32,42,52,6

3,13,23,33,43,53,6  

4,14,24,34,44,54,6 

5,15,25,35,45,55,6 

6,16,26,36,46,56,6 

n(s)=36   

E= Event of  getting a total of at most 10= 

{(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)} 

{(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)} 

{(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)} 

{(5,1)(5,2)(5,3)(5,4)(5,5)}  

{(6,1)(6,2)(6,3)(6,4)} 

Thereefore total number of favorable ways=33=n(E) 

Probability of getting a total of at most 10= `(n(E))/(n(s))=33/36=11/12` 

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Solution In a Single Throw of Two Dice, Find the Probability Of: a Total of at Most 10 Concept: Type of Event - Complementry.
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