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In a Single Throw of Two Dice, Find the Probability Of: An Odd Number as a Sum - ICSE Class 10 - Mathematics

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Question

In a single throw of two dice, find the probability of:  

 an odd number as a sum 

Solution

The  number of possible outcomes is `6xx6=36`,  We write them as given below:  

1,11,21,,31,41,51,6 

2,12,22,32,42,52,6

3,13,23,33,43,53,6  

4,14,24,34,44,54,6 

5,15,25,35,45,55,6 

6,16,26,36,46,56,6 

n(s)=36  

E=Event of getting an odd number as a sum ={(1,2)(1,4)(1,6)(2,1)(2,3)(2,5)(3,2)(3,4)(3,6)(4,1)(4,3)(4,5)(5,2)(5,6)(6,1)(6,3)(6,5)} 

n(E)=18 

Probability of getting an odd number as sum` (n(E))/(n(s))=18/36=1/2` 

  Is there an error in this question or solution?

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Solution In a Single Throw of Two Dice, Find the Probability Of: An Odd Number as a Sum Concept: Type of Event - Complementry.
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