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In a Single Throw of Two Dice, Find the Probability Of: an Odd Number on One Dice and a Number Less than Or Equal to 4 on the Other Dice. - ICSE Class 10 - Mathematics

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Question

In a single throw of two dice, find the probability of: 

an odd number on one dice and a number less than or equal to 4 on the other dice.   

Solution

The  number of possible outcomes is `6xx6=36`,  We write them as given below:  

1,11,21,,31,41,51,6 

2,12,22,32,42,52,6

3,13,23,33,43,53,6  

4,14,24,34,44,54,6 

5,15,25,35,45,55,6 

6,16,26,36,46,56,6 

n(s)=36    

E= Event of getting an odd number on dice 1 and a number less than or equal to 4  on  dice 2= 

{(1,1)(1,2)(1,3)(1,,4)(1,5)} 

{(2,1)(2,3)(2,5)} 

{(3,1)(3,2)(3,3)(3,4)(3,5)} 

{(4,1)(4,3)(4,5)} 

{(5,1)(5,2)(5,3)(5,4)} 

Therefore total number of favorable ways=20=n(E) 

Probability of getting an odd number on dice 1 and a number less than or equal to 4 on dice 2 =  `(n(E))/(n(s))=20/36=5/9` 

 

 

 

 

 

 

 

 

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Solution In a Single Throw of Two Dice, Find the Probability Of: an Odd Number on One Dice and a Number Less than Or Equal to 4 on the Other Dice. Concept: Type of Event - Complementry.
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