Two unbiased dice are thrown. Find the probability that the total of the numbers on the dice is greater than 10.

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#### Solution

If two dices are thrown simultaneously, then all the possible outcomes = 6^{2} = 36

∴ Total number of possible outcome, *n*(S) = 36

Let A = event where the the total of the numbers on the dices is greater than 10

Then the favourable outcomes are as follows:

A = {(5, 6), (6, 5), (6, 6)}

Number of favourable outcomes, *n*(A) = 3

Hence, required probability, P(A) = P (total of the numbers on the dices is greater than 10) = \[\frac{3}{36} = \frac{1}{12}\]

Concept: Axiomatic Approach to Probability

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