Answer in Brief
Two tungsten bulbs of power 50 W and 60 W work on 220 V potential difference. If they are connected in parallel, how much current will flow in the main conductor?
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Solution
P1 = 50W
`"R"_1 = "V"^2/"P"_1 = (220)^2/50`
`4840/5 Omega`
P2 =60 W
`"R"_2 = "V"_2/"P"_2 = (220)^2/60 4840/6 Omega`
`1/"R"_"P" = 1/"R"_1 +1/"R"_2 = 5/4840+6/4840 = 11/4840 = 1/440 `
`"R"_"P" = 440 Omega`
`"I" ="V"/"R"_"p" = 220/440 "A"= 0.5"A"`
Concept: Energy Transfer in an Electric Circuit
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