Sum

Two towers of heights 10 m and 30 m stand on a plane ground. If the distance between their feet is 15 m, find the distance between their tops

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#### Solution

By Phythagoras theorem, we have

`AC^2 = CE^2 + AE^2`

`⇒ AC^2 = 15^2 + 20^2 = 225 + 400 = 625`

`⇒ AC = \sqrt { 625 } = 25 m.`

Concept: Right-angled Triangles and Pythagoras Property

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