Two stable isotopes of lithium `""_3^6Li` and `""_3^7Li` `have respective abundances of 7.5% and 92.5%. These isotopes have masses 6.01512 u and 7.01600 u, respectively. Find the atomic mass of lithium.
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Solution
Mass of lithium isotope `""_3^6 Li`, m1 = 6.01512 u
Mass of lithium isotope `""_3^7 Li`, m2 = 7.01600 u
Abundance of `""_3^6 Li`, η1= 7.5%
Abundance of `""_3^7 Li`, η2= 92.5%
The atomic mass of lithium atom is given as:
`m = (m_1eta_1 + m_2eta_2)/(eta_1 + eta_2)`
`= (6.01512 xx 7.5 + 7.01600 xx 92.5)/(92.5 + 7.5)`
= 6.940934 u
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