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Two Squares Have Sides X Cm and (X + 4)Cm. the Sum of this Areas is 656 Cm2. Find the Sides of the Squares. - Mathematics

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Question

Two squares have sides x cm and (x + 4)cm. The sum of this areas is 656 cm2. Find the sides of the squares.

Solution

The given sides of two squares = x cm and (x + 4) cm

The sum of their areas = 656 cm2.

The area of the square = side × side.

∴ Area of the square = x (x + 4) cm2.

⇒ Given that sum of the areas is 656 cm2.

Hence by hypothesis, we have

⇒ x(x + 4) + x(x + 4) = 656

⇒ 2x (x + 4) = 656

⇒ 𝑥2 + 4𝑥 = 328 [dividing both side by 2]

⇒ 𝑥2 + 4c - 328 = 0

⇒ 𝑥2 + 20𝑥 - 16𝑥 - 328 = 0 [∵ By the method of factorisation]

⇒ 𝑥(𝑥 + 20) - 16(𝑥 + 20) = 0

⇒ (𝑥 + 20)(𝑥 - 16) = 0 ⇒ 𝑥 = -20 𝑜𝑟 𝑥 = 16

Case i: If x = 16; x + 4 = 20

∴ The sides of the squares are 16 cm and 20 cm.
Note: No negative value is considered as the sides will never be measured negatively.

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APPEARS IN

 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.7 | Q: 3 | Page no. 51
 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.7 | Q: 3 | Page no. 51
 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.7 | Q: 3 | Page no. 51
 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.7 | Q: 3 | Page no. 51
Solution Two Squares Have Sides X Cm and (X + 4)Cm. the Sum of this Areas is 656 Cm2. Find the Sides of the Squares. Concept: Solutions of Quadratic Equations by Factorization.
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