# Two sources of sound are separated by a distance of 4 m. They both emit sound with the same amplitude and frequency (330 Hz), but they are 180° out of phase. - Physics

Sum

Two sources of sound are separated by a distance of 4 m. They both emit sound with the same amplitude and frequency (330 Hz), but they are 180° out of phase. At what points between the two sources, will the sound intensity be maximum?

#### Solution

∴ λ = "v"/"n"=330/330 = 1 m

Directly at the center of two sources of sound, path difference is zero. But since the waves are 180° out of phase, two maxima on either side should be at a distance of λ/4 from the point at the center. Other maxima will be located each λ/2 further along.

Thus, the sound intensity will be maximum at ± 0.25, ± 0.75, ± 1.25, ± 1.75 m from the point at the center.

Concept: Speed of Wave Motion
Is there an error in this question or solution?

#### APPEARS IN

Balbharati Physics 12th Standard HSC Maharashtra State Board
Chapter 6 Superposition of Waves
Exercises | Q 12 | Page 157