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Two sources of sound are separated by a distance of 4 m. They both emit sound with the same amplitude and frequency (330 Hz), but they are 180° out of phase. - Physics

Sum

Two sources of sound are separated by a distance of 4 m. They both emit sound with the same amplitude and frequency (330 Hz), but they are 180° out of phase. At what points between the two sources, will the sound intensity be maximum?

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Solution

∴ λ = `"v"/"n"=330/330` = 1 m

Directly at the center of two sources of sound, path difference is zero. But since the waves are 180° out of phase, two maxima on either side should be at a distance of `λ/4` from the point at the center. Other maxima will be located each `λ/2` further along.

Thus, the sound intensity will be maximum at ± 0.25, ± 0.75, ± 1.25, ± 1.75 m from the point at the center.

Concept: Speed of Wave Motion
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APPEARS IN

Balbharati Physics 12th Standard HSC Maharashtra State Board
Chapter 6 Superposition of Waves
Exercises | Q 12 | Page 157
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