# Two sources of sound are separated by a distance of 4 m. They both emit sound with the same amplitude and frequency (330 Hz), but they are 180° out of phase. - Physics

Sum

Two sources of sound are separated by a distance of 4 m. They both emit sound with the same amplitude and frequency (330 Hz), but they are 180° out of phase. At what points between the two sources, will the sound intensity be maximum?

#### Solution

∴ λ = "v"/"n"=330/330 = 1 m

The path difference between two sources of sound is zero when they are directly in the centre of each other. However, because the waves are 180° out of phase, two maxima on either side should be at a distance of λ/4 from the centre. Other maxima will be located each λ/2 along the way.

As a result, the maximum sound intensity will be ± 0.25, ± 0.75, ± 1.25, and ± 1.75 m from the point at the centre.

Concept: Speed of Wave Motion
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#### APPEARS IN

Balbharati Physics 12th Standard HSC Maharashtra State Board
Chapter 6 Superposition of Waves
Exercises | Q 12 | Page 157