Sum

Two sound waves travel at a speed of 330 m/s. If their frequencies are also identical and are equal to 540 Hz, what will be the phase difference between the waves at points 3.5 m from one source and 3 m from the other if the sources are in phase?

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#### Solution

**Data:** v = 330 m/s, n_{1} = n_{2 }= 540 Hz

v = n × λ

∴ λ = `330/540` = 0.61 m

Here, the path difference = 3.5 − 3 m = 0.5 m

Phase difference = `(2π)/λxx"Path difference"`

= `(2π)/0.61xx0.5` = 1.64π rad

Concept: Beats

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