Sum
Two sound waves travel at a speed of 330 m/s. If their frequencies are also identical and are equal to 540 Hz, what will be the phase difference between the waves at points 3.5 m from one source and 3 m from the other if the sources are in phase?
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Solution
Data: v = 330 m/s, n1 = n2 = 540 Hz
v = n × λ
∴ λ = `330/540` = 0.61 m
Here, the path difference = 3.5 − 3 m = 0.5 m
Phase difference = `(2π)/λxx"Path difference"`
= `(2π)/0.61xx0.5` = 1.64π rad
Concept: Beats
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