# Two Periodic Waves of Amplitudes A1 and A2 Pass Thorough a Region. If A1 > A2, the Difference in the Maximum and Minimum Resultant Amplitude Possible is - Physics

MCQ

Two periodic waves of amplitudes A1 and A2 pass thorough a region. If A1 > A2, the difference in the maximum and minimum resultant amplitude possible is

• 2A1

• 2A2

•  A1 + A2

•  A1 − A2

#### Solution

2A2
We know resultant amplitude is given by
$A_{net} = \sqrt{A_1^2 + A_2^2 + 2 A_1 A_2 \cos\phi}$ For maximum resultant amplitude $A_\max = A_1 + A_2$ For minimum resultant amplitude $A_\min = A_1 - A_2$
So, the difference between Amax and Amin is
$A_\max - A_\min = A_1 + A_2 - A_1 + A_2 = 2 A_2$

Concept: Speed of Wave Motion
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#### APPEARS IN

HC Verma Class 11, 12 Concepts of Physics 1
Chapter 15 Wave Motion and Waves on a String
MCQ | Q 15 | Page 322