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Two Particles Perform Linear Simple. Harmonic Motion Along the Same Path of Length 2a and Period T as Shown In the Graph Below. the Phase Difference Between Them is - Physics

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MCQ

Two particles perform linear simple harmonic motion along the same path of length 2A and period T as shown in the graph below. The phase difference between them is ___________.

Options

  • Zero rad

  • `pi/4` rad

  • `pi/2` rad

  • `(3pi)/4` rad

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Solution

` pi/4 rad`

Let the equation of waves be Asin( ωt + Φ )
For wave with peak at t = 0, the equation becomes,
y = Asin( ωt + 90° )
For the wave with displacement `A/sqrt2 at  t` = 0
`A/sqrt2 = Asin(Φ)`

⇒ Φ = 45° = `pi/4`
Hence this is the phase difference between the waves.

 
Concept: Differential Equation of Linear S.H.M.
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