#### Question

Two insulated charged copper spheres A and B have their centers separated by a distance of 50 cm. What is the mutual force of electrostatic repulsion if the charge on each is 6.5 × 10^{−7} C? The radii of A and B are negligible compared to the distance of separation

#### Solution

Charge on sphere A, *q*_{A} = Charge on sphere B, *q*_{B} = 6.5 × 10^{−7} C

Distance between the spheres, *r* = 50 cm = 0.5 m

Force of repulsion between the two spheres,

`F=(q_Aq_B)/(4piin_0r^2)`

Where,

∈_{0} = Free space permittivity

`1/(4piin_0)=9xx10^9 Nm^2C^-2`

`F=(9xx10^9xx(6.5xx10^-7)^2)/((0.5)^2)`

= 1.52 × 10^{−2} N

Therefore, the force between the two spheres is 1.52 × 10^{−2} N.

Is there an error in this question or solution?

Solution Two Insulated Charged Copper Spheres a and B Have Their Centers Separated by a Distance of 50 Cm. What is the Mutual Force of Electrostatic Repulsion If the Charge on Each is 6.5 × 10^−7 C? the Radii of a and B Are Negligible Compared to the Distance of Separation Concept: Charging by Induction.