Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12
Advertisement Remove all ads

Two Identical Particles, Each with a Charge of 2.0 × 10−4 C and Mass of 10 G, Are Kept at a Separation of 10 Cm and Then Released. What Would Be Speed of Particles When the Separation Becomes Large? - Physics

Numerical

Two identical particles, each with a charge of 2.0 × 10−4 C and mass of 10 g, are kept at a separation of 10 cm and then released. What would be the speed of the particles when the separation becomes large?

Advertisement Remove all ads

Solution

Given:
Magnitude of charges, q  = 2.0 × 10−4 C
Mass of particles, m = 10 g = 0.01 kg
Separation between the charges, r = 10 cm = 0.1 m
Force of repulsion,  

\[F = \frac{1}{4\pi \epsilon_0}\frac{q^2}{r^2}\]

\[F = 1 . 8 \times {10}^4 \] N
\[F = m \times a\]
\[ \Rightarrow a = 1 . 8 \times {10}^6 \text{ m/ s}^2\]

Now,

\[v^2 = u^2 + 2\] as
\[ v^2 = 0 + 2 \times 1 . 8 \times {10}^6 \times 10 \times {10}^{- 2} \]
\[v = \sqrt{36 \times {10}^4}\]
\[v = 600 \] m/s

  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 7 Electric Field and Potential
Q 68 | Page 124
Advertisement Remove all ads

Video TutorialsVIEW ALL [2]

Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×