Question

Two electric bulbs P and Q have their resistances in the ratio of 1 : 2. They are connected in series across a battery. Find the ratio of the power dissipation in these bulbs

Answer 1

For series combination, power dissipated by a bulb is directly proportional to its resistance.

Thus,

`P_1/P_2 = R_1/R_2 = 1/2`