Two electric bulbs P and Q have their resistances in the ratio of 1 : 2. They are connected in series across a battery. Find the ratio of the power dissipation in these bulbs
For series combination, power dissipated by a bulb is directly proportional to its resistance.
`P_1/P_2 = R_1/R_2 = 1/2`
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- Combination of Resistors - Series and Parallel