Maharashtra State BoardHSC Science (General) 11th
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Two dice are thrown together. Let A be the event 'getting 6 on the first die' and B be the event 'getting 2 on the second die'. Are the events A and B independent? - Mathematics and Statistics

Sum

Two dice are thrown together. Let A be the event 'getting 6 on the first die' and B be the event 'getting 2 on the second die'. Are the events A and B independent?

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Solution

When two dice are thrown, the sample space is

S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

∴ n(S) = 36

Let event A: Getting 6 on the first die.

∴ A = {(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

∴ n(A) = 6

∴ P(A) = `("n"("A"))/("n"("S")) = 6/36 = 1/6`

Let event B: Gettting 2 on the second die.

∴ B = {(1, 2), (2, 2), (3, 2), (4, 2), (5, 2), (6, 2)}

∴ n(B) = 6

∴ P(B) = `("n"("B"))/("n"("S")) = 6/36 = 1/6`

Now, A ∩ B = {(6, 2)}

∴ n(A ∩ B) = 1

∴ P(A ∩ B) = `("n"("A" ∩ "B"))/("n"("S")) = 1/36`  ...(i)

P(A) × P(B) = `1/6 xx 1/6 = 1/36`   ...(ii)

 From (i) and (ii), we ge

P(A ∩ B)  = P(A) × P(B)

∴ A and B are independent events.

Concept: Independent Events
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