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Sum

Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table:

Sum |
Frequency |

2 | 14 |

3 | 30 |

4 | 42 |

5 | 55 |

6 | 72 |

7 | 75 |

8 | 70 |

9 | 53 |

10 | 46 |

11 | 28 |

12 | 15 |

If the dice are thrown once more, what is the probability of getting a sum between 8 and 12?

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#### Solution

Total number of times, when two dice are thrown simultaneously, n(S) = 500

The number of times of getting a sum between 8 and 12,

n(E_{3}) = 53 + 46 + 28 = 127

∴ Required probability = `(n(E_3))/(n(S)) = 127/500` = 0.254

Hence, the probability of getting a sum between 8 and 12 is 0.254

Concept: Probability - an Experimental Approach

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