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Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table: Sum Frequency - Mathematics

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Sum

Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table:

Sum Frequency
2 14
3 30
4 42
5 55
6 72
7 75
8 70
9 53
10 46
11 28
12 15

If the dice are thrown once more, what is the probability of getting a sum between 8 and 12?

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Solution

Total number of times, when two dice are thrown simultaneously, n(S) = 500

The number of times of getting a sum between 8 and 12,

n(E3) = 53 + 46 + 28 = 127

∴ Required probability = `(n(E_3))/(n(S)) = 127/500` = 0.254

Hence, the probability of getting a sum between 8 and 12 is 0.254

Concept: Probability - an Experimental Approach
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APPEARS IN

NCERT Mathematics Exemplar Class 9
Chapter 14 Statistics & Probability
Exercise 14.3 | Q 17.(iv) | Page 143

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