# Two Cubes, Each of Volume 512 Cm3 Are Joined End to End. Find the Surface Area of the Resulting Cuboid. - Mathematics

Two cubes, each of volume 512 cm3 are joined end to end. Find the surface area of the resulting cuboid.

#### Solution

$\text { Two cubes each of volume 512 } {cm}^3\text { are joined end to end . }$

$\text { Now, volume of a cube = (side ) }^3$

$\Rightarrow 512 = \text { (side ) }^3$

$\Rightarrow\text { Side of the cube = }\sqrt[3]{512} = 8 cm$

$\text { If the cubes area joined side by side, then the length of the resulting cuboid is 2 } + \times 8 cm = 16 cm .$

$\text { Breadth = 8 cm }$

$\text { Height = 8 cm }$

$\therefore \text { Surface area of the cuboid = 2 } \times\text { (length }\times \text { breadth + breadth } \times \text{ height + length } \times \text { height) }$

$= 2 \times (16 \times 8 + 8 \times 8 + 16 \times 8)$

$= 2 \times (128 + 64 + 128)$

$= 640 {cm}^2$

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#### APPEARS IN

RD Sharma Class 8 Maths
Chapter 21 Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube)
Exercise 21.4 | Q 12 | Page 30