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Two Cubes, Each of Volume 512 Cm3 Are Joined End to End. Find the Surface Area of the Resulting Cuboid. - Mathematics

Answer in Brief

Two cubes, each of volume 512 cm3 are joined end to end. Find the surface area of the resulting cuboid.

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Solution

\[\text { Two cubes each of volume 512 } {cm}^3\text {  are joined end to end .  }\]

\[\text { Now, volume of a cube = (side ) }^3 \]

\[ \Rightarrow 512 = \text { (side ) }^3 \]

\[ \Rightarrow\text {  Side of the cube =  }\sqrt[3]{512} = 8 cm \]

\[\text { If the cubes area joined side by side, then the length of the resulting cuboid is 2 } + \times 8 cm = 16 cm . \]

\[\text { Breadth = 8 cm } \]

\[\text { Height = 8 cm }\]

\[ \therefore \text { Surface area of the cuboid = 2 } \times\text {  (length  }\times \text { breadth + breadth } \times \text{ height + length } \times \text { height) }\]

\[ = 2 \times (16 \times 8 + 8 \times 8 + 16 \times 8)\]

\[ = 2 \times (128 + 64 + 128)\]

\[ = 640 {cm}^2\]

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APPEARS IN

RD Sharma Class 8 Maths
Chapter 21 Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube)
Exercise 21.4 | Q 12 | Page 30
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