Two cars start together in the same direction from the same place. The first cargoes at uniform speed of 10 km h-1. The second car goes at a speed of 8 km h-1 in the first hour and thereafter increasing the speed by 0.5 km h-1 each succeeding hour. After how many hours will the two cars meet?
Let the two cars meet after n hours.
That means the two cars travel the same distance in n hours.
Distance travelled by the `1^(st)` car in n hours= `10xxn km` Distance travelled by the 2^nd car in n hours=`n/2[2xx8+(n-1)xx0.5]km`
Thus , the two cars will meet after 9 hours.d08