Sum
Two cars start together in the same direction from the same place. The first cargoes at uniform speed of 10 km h-1. The second car goes at a speed of 8 km h-1 in the first hour and thereafter increasing the speed by 0.5 km h-1 each succeeding hour. After how many hours will the two cars meet?
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Solution
Let the two cars meet after n hours.
That means the two cars travel the same distance in n hours.
Distance travelled by the `1^(st)` car in n hours= `10xxn km` Distance travelled by the 2^nd car in n hours=`n/2[2xx8+(n-1)xx0.5]km`
`⇒ 10xxn=n/2[2xx8+(n-1)xx0.5]`
`⇒20=16+0.5n-0.5`
`⇒0.5n=4.5`
`⇒n=9`
Thus , the two cars will meet after 9 hours.d08
Concept: Arithmetic Progression - Finding Sum of Their First ‘N’ Terms.
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