#### Question

Two bodies A and B having equal surface areas are maintained at temperature 10°C and 20°C. The thermal radiation emitted in a given time by A and B are in the ratio

1 : 1.15

1 : 2

1 : 4

1 : 16

#### Solution

1 : 1.15

From Stefan-Boltzmann law, energy of the thermal radiation emitted per unit time by a blackbody of surface area* A* is given by `u = σAT^4 `

Here, `σ` is Stefan-Boltzmann constant.

`(uA)/(uB)` = `"T"_"A"^4/(T_B^4)`

`(u_A)/ (u_B) = ( 273 +10 )^4/ (273 + 20 )^4`

`uA/uB = 1/1.15`

Is there an error in this question or solution?

Solution Two Bodies a and B Having Equal Surface Areas Are Maintained at Temperature 10°C and 20°C. the Thermal Radiation Emitted in a Given Time by a and B Are in the Ratio Concept: Heat Transfer - Radiation.