#### Question

Show that:

(i) `2(cos^2 45º + tan^2 60º) – 6(sin^2 45º – tan^2 30º) = 6`

(ii) `2(cos^4 60º + sin^4 30º) – (tan^2 60º + cot^2 45º) + 3 sec^2 30º = 1/4`

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Solution for question: Show that: (i) 2(cos^2 45º + tan^2 60º) – 6(sin^2 45º – tan^2 30º) = 6, (ii) 2(cos^4 60º + sin^4 30º) – (tan^2 60º + cot^2 45º) + 3 sec^2 30º = 1/4 concept: Trigonometric Ratios of Some Specific Angles. For the course CBSE