#### Question

Prove the following :

`(cos(90°−A) sin(90°−A))/tan(90°−A) - sin^2 A = 0`

#### Solution

We have to prove `(cos(90°−A) sin(90°−A))/tan(90°−A) - sin^2 A = 0`

Left hand side

`= (cos (90^@ - A). sin(90^@ - A))/(tan (90^@ - A))`

`= (sinA.cosA)/cot A = sin^2 A``

`= (sin A.cos A.sin A)/cos A`

`= sin ^2 A`

= Right hand side

Proved

Is there an error in this question or solution?

#### APPEARS IN

Solution Prove the Following :`(Cos(90°−A) Sin(90°−A))/Tan(90°−A) - Sin^2 a = 0 Concept: Trigonometric Ratios of Some Specific Angles.