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# If Sin 3a = Cos (A – 26°), Where 3a is an Acute Angle, Find the Value of a =? - CBSE Class 10 - Mathematics

ConceptTrigonometric Ratios of Some Specific Angles

#### Question

If Sin 3A = cos (A – 26°), where 3A is an acute angle, find the value of A =?

#### Solution

Cos 𝜃 = sin (90° - 𝜃)

⇒ Cos (A – 26) = sin (90° −(A− 26°))

⇒ Sin 3A = sin (90° − (A – 26))

Equating angles on both sides

3A = 90° − A + 26°

4A = 116° A = 116/4 = 29^@

∴ A = 29^@

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Solution If Sin 3a = Cos (A – 26°), Where 3a is an Acute Angle, Find the Value of a =? Concept: Trigonometric Ratios of Some Specific Angles.
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