#### Question

Evaluate the following

`sec 11^@/(cosec 79^@)`

#### Solution

Given that `sec 11^@/(cosec 79^@)`

Since `sec(90 - theta) = cosec theta`

`=> sec 11/(cosec 79) = (sec (90 - 79))/(cosec 79)`

`=> sec 11/(cosec 79) = (cosec 79)/(cosec 79)`

`=> sec 11/(cosec 79) = 1`

Therefore `sec 11/(cosec 79) = 1`

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#### APPEARS IN

Solution Evaluate the Following Sec11∘/Cosec79∘ Concept: Trigonometric Ratios of Some Specific Angles.