#### Question

In the following, trigonometric ratios are given. Find the values of the other trigonometric ratios.

`cosec theta = sqrt10`

#### Solution

consider a right-angled Δ^{le} ABC, we get

Let x be the adjacent side.

By applying Pythagoras theorem

𝐴𝐶^{2} = 𝐴𝐵^{2} + 𝐵𝐶^{2}

`(sqrt10)^2 = 1^2 + x^2`

x^{2} = 10 − 1 = 9

x = 3

`sin theta = 1/cosec theta = 1/sqrt10`

`cos theta = "adjacent"/"hypotenuse" = 3/sqrt10`

`tan theta = "opposite sides"/"adjacebt side" = 1/3`

`sec theta = 1/cos theta = sqrt10/3`

`cot theta = 1/tan theta = (1/1)/3 = 3`

Is there an error in this question or solution?

#### APPEARS IN

Solution In the Following, Trigonometric Ratios is Given. Find the Values of the Other Trigonometric Ratios. `Cosec Theta = Sqrt10` Concept: Trigonometric Ratios.