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If `Sin Theta = A/B` Find Sec θ + Tan θ in Terms of a and B. - CBSE Class 10 - Mathematics

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Question

If `sin theta = a/b` find sec θ + tan θ in terms of a and b.

Solution

We know `sin theta = "𝑜𝑝𝑝𝑜𝑠𝑖𝑡𝑒 𝑠𝑖𝑑𝑒"/"ℎ𝑦𝑝𝑜𝑡𝑒𝑛𝑢𝑠𝑒"`

Let x be the adjacent side

By applying Pythagoras theorem

𝐴𝐶2 = 𝐴𝐵2 + 𝐵𝐶2

b2 = a2 + x2

x2 = b2 − a2

`x = sqrt(b^2 - a^2)`

`sec theta = (AB)/(BC) = b/(sqrt(b^2 - a^2))`

`tan theta = (AB)/(BC) = a/(sqrt(b^2 - a^2))`

`sec theta + tan theta = b/(b^2 - a^2) + a/(sqrt(b^2 - a^2))`

`= (b + a)/(sqrt(b^2 - a^2)) = (b+ a)/sqrt((b + a)(b - a)) = (b + a)/sqrt(b + a) - 1/(sqrt(b - a)) = sqrt((b + a)/(b - a))`

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Solution If `Sin Theta = A/B` Find Sec θ + Tan θ in Terms of a and B. Concept: Trigonometric Ratios.
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