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Evaluate tan65°/cot25° - CBSE Class 10 - Mathematics

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Question

`\text{Evaluate }\frac{\tan 65^\circ }{\cot 25^\circ}`

 

Solution

65° + 25° = 90°

`\therefore \frac{\tan 65^\circ }{\cot 25^\circ }=\frac{\tan(90^\circ -25^\circ )}{\cot25^\circ }=\frac{\cot 25^\circ}{\cot 25^\circ }=1`

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Solution Evaluate tan65°/cot25° Concept: Trigonometric Ratios of Complementary Angles.
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