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Solution - (cot54º/tan36º)+(tan20º/cot70º)−2 - Trigonometric Ratios of Complementary Angles

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ConceptTrigonometric Ratios of Complementary Angles  

Question

`(\text{i})\text{ }\frac{\cot 54^\text{o}}{\tan36^\text{o}}+\frac{\tan 20^\text{o}}{\cot 70^\text{o}}-2`

(ii) sec 50º sin 40° + cos 40º cosec 50º 

Solution

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Reference Material

Solution for question: (cot54º/tan36º)+(tan20º/cot70º)−2 concept: Trigonometric Ratios of Complementary Angles. For the course CBSE
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