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# If a = B = 60°. Verify Tan (A - B) = (Tan a - Tan B)/(1 + Tan Tan B) - CBSE Class 10 - Mathematics

ConceptTrigonometric Ratios of an Acute Angle of a Right-angled Triangle

#### Question

If A = B = 60°. Verify tan (A - B) = (tan A - tan B)/(1 + tan   tan B)

#### Solution

Given:

A = B = 60°  ......(1)

To verify:

tan (A - B) = (tan A - tanB)/(1 + tan Atan B) ......(2)

Now consider LHS of the expression to be verified in equation (2)

Therefore.

tan (A - B) = tan (B - B)

= tan 0

= 0

Now consider RHS of the expression to be verified in equation (2)

Therefore

Now by substituting the value of A and B from equation (1) in the above expression

We get,

(tan A - tan B)/(1 + tanA tan B) = (tan B - tan B)/(1 + tanB tan B)

= 0/(1 + tan^2 B)

= 0

Hence it is verified that,

tan (A - B) = (tan A - tan B)/(1 + tan   tan B)

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Solution If a = B = 60°. Verify Tan (A - B) = (Tan a - Tan B)/(1 + Tan Tan B) Concept: Trigonometric Ratios of an Acute Angle of a Right-angled Triangle.
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