# Solution - Trigonometric Identities

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ConceptTrigonometric Identities

#### Question

Prove that sin6θ + cos6θ = 1 – 3 sin2θ. cos2θ.

#### Solution

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#### Similar questions

Prove the following identities, where the angles involved are acute angles for which the expressions are defined.

(1+ secA)/sec A = (sin^2A)/(1-cosA)

[Hint : Simplify LHS and RHS separately]

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Prove that \frac{\sin \theta -\cos \theta }{\sin \theta +\cos \theta }+\frac{\sin\theta +\cos \theta }{\sin \theta -\cos \theta }=\frac{2}{2\sin^{2}\theta -1}

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Prove that: (1 – sinθ + cosθ)^2 = 2(1 + cosθ)(1 – sinθ)

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If sinθ + cosθ = p and secθ + cosecθ = q, show that q(p2 – 1) = 2p

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