#### Question

Prove that ` \frac{\sin \theta -\cos \theta +1}{\sin\theta +\cos \theta -1}=\frac{1}{\sec \theta -\tan \theta }` using the identity sec^{2} θ = 1 + tan^{2} θ.

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#### Reference Material

Solution for question: Prove that (sinθ−cosθ+1)/(sinθ+cosθ−1)=1/(secθ−tanθ) using the identity sec^2 θ = 1 + tan^2 θ. concept: Trigonometric Identities. For the course CBSE