#### Question

In a Δ ABC, with usual notations prove that:` (a -bcos C) /(b -a cos C )= cos B/ cos A`

#### Solution

Consider L.H.S. `=(a-bcosC)/(b-acosC)`

`=(b cosC+c cosB-b cosC)/(a cosC+c cosA-a cosC)`

`=(c cosB)/(c cosA) `

`=cosB/cosA=R.H.S`

`therefore (a-bcosC)/(b-acosC)=(cosB)/(cosA)`

Is there an error in this question or solution?

#### APPEARS IN

Solution for question: In a Δ ABC, with usual notations prove that: (a -bcos C) /(b -a cos C )= cos B/ cos A concept: Trigonometric Functions - Solution of a Triangle. For the courses HSC Science (Electronics), HSC Science (General) , HSC Arts, HSC Science (Computer Science)